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jprosenbaum8908
Calcite | Level 5

Let's say I have 100 Temporary Employees, variable label TE, and they are assigned a number 1 -100. I want to assign the Temp Employ a Rotation number, variable label RO, of 1 through 3 repeatedly and have it start with a random rotation number. So if the random number generated for the first TE is RO = 2, I want the next RO=3, then start the cycle over of assigning RO of 1-3 for the rest of the TEs. I know this is basic, but I am struggling how to write this.

here is my example:

Data haveemp;

INPUT TE;

Datalines;

1

2

3

4

5

6

7

8

9

10

11

12

;

data wantrot;

length RO 8;

set haveemp;

if TE = 1 then RO = ceil(4*ranuni(0));

Do i = 2 to 12;

...

end;

run;

I am not sure what to do after the do statement. I have a mod(n-1,3)+1 type of thinking for the other ROs but I am not sure how to ensure a proper cycle with the random number generated for the first TE.

Any help would be appreciated.

1 ACCEPTED SOLUTION

Accepted Solutions
Quentin
Super User

Maybe something like this:

127  data want;
128    set haveemp;
129    retain RO;
130    if TE=1 then RO=ceil(3*ranuni(0));
131    else RO=mod(RO,3)+1;
132    put _all_;
133  run;

TE=1 RO=3 _ERROR_=0 _N_=1
TE=2 RO=1 _ERROR_=0 _N_=2
TE=3 RO=2 _ERROR_=0 _N_=3
TE=4 RO=3 _ERROR_=0 _N_=4
TE=5 RO=1 _ERROR_=0 _N_=5
TE=6 RO=2 _ERROR_=0 _N_=6
TE=7 RO=3 _ERROR_=0 _N_=7
TE=8 RO=1 _ERROR_=0 _N_=8
TE=9 RO=2 _ERROR_=0 _N_=9
TE=10 RO=3 _ERROR_=0 _N_=10
TE=11 RO=1 _ERROR_=0 _N_=11
TE=12 RO=2 _ERROR_=0 _N_=12

View solution in original post

3 REPLIES 3
data_null__
Jade | Level 19

I like PROC PLAN for this.

data _null_;
  
call streaminit(34567);
   call symputx('ib',rand('table',1/3,1/3));
   run;
%put NOTE: &=ib &=sysrandom;

proc plan seed=998877;
  
factors to=100 ordered ro=1 of 3 cyclic(&ib) /noprint;
  
output out=plan;
   run;
  
quit;
proc print;
  
run;

6-10-2015 12-32-46 PM.png
Quentin
Super User

Maybe something like this:

127  data want;
128    set haveemp;
129    retain RO;
130    if TE=1 then RO=ceil(3*ranuni(0));
131    else RO=mod(RO,3)+1;
132    put _all_;
133  run;

TE=1 RO=3 _ERROR_=0 _N_=1
TE=2 RO=1 _ERROR_=0 _N_=2
TE=3 RO=2 _ERROR_=0 _N_=3
TE=4 RO=3 _ERROR_=0 _N_=4
TE=5 RO=1 _ERROR_=0 _N_=5
TE=6 RO=2 _ERROR_=0 _N_=6
TE=7 RO=3 _ERROR_=0 _N_=7
TE=8 RO=1 _ERROR_=0 _N_=8
TE=9 RO=2 _ERROR_=0 _N_=9
TE=10 RO=3 _ERROR_=0 _N_=10
TE=11 RO=1 _ERROR_=0 _N_=11
TE=12 RO=2 _ERROR_=0 _N_=12

jprosenbaum8908
Calcite | Level 5

Thanks, yes that worked.

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