You may need to rethink what your are requesting. Averages of percentages or rates are seldom properly interpreted or interpretable.
Example If I have 10,000 students in one school and the percent that get an A is 20% (2000 students) and I average that with a school that has 5 students and 100% get an A would it be appropriate to say that (20+100)/2 percent or 60 percent of students overall got an A?
You have to sum numerators and denominators and then calculate the percentage: (2000 + 5)/(10000 +5) which is about 20.04 percent.
Averaging rates such as percentages really on works when the denominators are the same (or when the samples are pretty close in size with similar rates the difference may disappear in rounding)
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