dear all,
using INTNX('dtmonth' , var1 , 0 , 'e' )
gives me the last day of the month of var1 ==> 31JAN2020:23:59:59
however I want 31JAN2020:00:00:00,
Of course I can subtract (24h*60m*60s) - 1: intnx('dtmonth', var1 , 0 ,'e' ) - 86399
but is there a nicer way ??
H.
You could use INTNX() a second time.
intnx('dtday',INTNX('dtmonth' , var1 , 0 , 'e' ),0,'b')
You could switch to/from dates
dhms(INTNX('month' , datepart(var1) , 0 , 'e' ),0,0,0)
You could use INTNX() a second time.
intnx('dtday',INTNX('dtmonth' , var1 , 0 , 'e' ),0,'b')
You could switch to/from dates
dhms(INTNX('month' , datepart(var1) , 0 , 'e' ),0,0,0)
Here is one way
data _null_;
dt = dhms(intnx('month' , today() , 0 , 'e' ), 0, 0, 0);
put dt= datetime20.;
run;
Available on demand!
Missed SAS Innovate Las Vegas? Watch all the action for free! View the keynotes, general sessions and 22 breakouts on demand.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.