dear all,
using INTNX('dtmonth' , var1 , 0 , 'e' )
gives me the last day of the month of var1 ==> 31JAN2020:23:59:59
however I want 31JAN2020:00:00:00,
Of course I can subtract (24h*60m*60s) - 1: intnx('dtmonth', var1 , 0 ,'e' ) - 86399
but is there a nicer way ??
H.
You could use INTNX() a second time.
intnx('dtday',INTNX('dtmonth' , var1 , 0 , 'e' ),0,'b')
You could switch to/from dates
dhms(INTNX('month' , datepart(var1) , 0 , 'e' ),0,0,0)
You could use INTNX() a second time.
intnx('dtday',INTNX('dtmonth' , var1 , 0 , 'e' ),0,'b')
You could switch to/from dates
dhms(INTNX('month' , datepart(var1) , 0 , 'e' ),0,0,0)
Here is one way
data _null_;
dt = dhms(intnx('month' , today() , 0 , 'e' ), 0, 0, 0);
put dt= datetime20.;
run;
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