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Jaheuk
Obsidian | Level 7

dear all,

 

using INTNX('dtmonth' , var1 , 0 , 'e' )

 

gives me the last day of the month of var1 ==> 31JAN2020:23:59:59

 

however I want 31JAN2020:00:00:00,

 

Of course I can subtract (24h*60m*60s) - 1:  intnx('dtmonth', var1 , 0 ,'e' ) - 86399

 

but is there a nicer way ??

 

H.

1 ACCEPTED SOLUTION

Accepted Solutions
Tom
Super User Tom
Super User

You could use INTNX() a second time.

intnx('dtday',INTNX('dtmonth' , var1 , 0 , 'e' ),0,'b')

You could switch to/from dates

dhms(INTNX('month' , datepart(var1) , 0 , 'e' ),0,0,0)

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2 REPLIES 2
Tom
Super User Tom
Super User

You could use INTNX() a second time.

intnx('dtday',INTNX('dtmonth' , var1 , 0 , 'e' ),0,'b')

You could switch to/from dates

dhms(INTNX('month' , datepart(var1) , 0 , 'e' ),0,0,0)
PeterClemmensen
Tourmaline | Level 20

Here is one way

 

data _null_;
    dt = dhms(intnx('month' , today() , 0 , 'e' ), 0, 0, 0);
    put dt= datetime20.;
run;

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