BookmarkSubscribeRSS Feed
☑ This topic is solved. Need further help from the community? Please sign in and ask a new question.
SAS-questioner
Obsidian | Level 7

Hi, I have a question about how to put duplicates into different groups based on the original order? I have a data like below:

 

ID  condition
1        A
1        A
2        B
2        B
3        A
3        A
3        B
3        B
4        B
4        B
4        A
4        A
5        A
5        A
5       B
5       B
5       A
5       A       

The data is like above, basically, there are five situations: 1. all As; 2, all Bs; 3, A first and then B; 4, B first and then A; 5, A first and then B, and then A.

I want to keep the original order, which means I can't use proc sort, because after I use proc sort, AABBAA or BBAA will become AAAABB and AABB.

What I want to do is to put ID with all As in group 1, put ID with all Bs in group 2, and put ID with A first and then B in to group 3. So, for the rest of patterns like B first and then A, or A first and then B, and then A can be removed. I am wondering if there is a way to do it? Hopefully that I express myself clearly. Thank you!

1 ACCEPTED SOLUTION

Accepted Solutions
Tom
Super User Tom
Super User

If you just want those specific groups AB, BA, A , B and perhaps none then you could do something like this:

data want;
  do row=1 by 1 until (last.id);
    set have;
    by id;
    if condition='A' then a=min(a,row);
    else if condition='B' then b=min(b,row);
  end;
  length group $2 ;
  if . < a < b then group='AB';
  else if . < b < a then group='BA';
  else if . < b then group='B';
  else if . < a then group='A';
  keep id group;
run;

Result

Obs    ID    group

 1     1      A
 2     2      B
 3     3      AB
 4     4      BA
 5     5      AB

If you also want to look for longer patterns, like ABA you might use something like:

data want;
  set have;
  by id condition notsorted;
  length group $8 ;
  retain group;
  if first.id then group=' ';
  if first.condition then group=cats(group,condition);
  if last.id;
  keep id group;
run;

Result

Obs    ID    group

 1     1      A
 2     2      B
 3     3      AB
 4     4      BA
 5     5      ABA

 

 

View solution in original post

2 REPLIES 2
Tom
Super User Tom
Super User

If you just want those specific groups AB, BA, A , B and perhaps none then you could do something like this:

data want;
  do row=1 by 1 until (last.id);
    set have;
    by id;
    if condition='A' then a=min(a,row);
    else if condition='B' then b=min(b,row);
  end;
  length group $2 ;
  if . < a < b then group='AB';
  else if . < b < a then group='BA';
  else if . < b then group='B';
  else if . < a then group='A';
  keep id group;
run;

Result

Obs    ID    group

 1     1      A
 2     2      B
 3     3      AB
 4     4      BA
 5     5      AB

If you also want to look for longer patterns, like ABA you might use something like:

data want;
  set have;
  by id condition notsorted;
  length group $8 ;
  retain group;
  if first.id then group=' ';
  if first.condition then group=cats(group,condition);
  if last.id;
  keep id group;
run;

Result

Obs    ID    group

 1     1      A
 2     2      B
 3     3      AB
 4     4      BA
 5     5      ABA

 

 

hackathon24-white-horiz.png

The 2025 SAS Hackathon Kicks Off on June 11!

Watch the live Hackathon Kickoff to get all the essential information about the SAS Hackathon—including how to join, how to participate, and expert tips for success.

YouTube LinkedIn

How to Concatenate Values

Learn how use the CAT functions in SAS to join values from multiple variables into a single value.

Find more tutorials on the SAS Users YouTube channel.

SAS Training: Just a Click Away

 Ready to level-up your skills? Choose your own adventure.

Browse our catalog!

Discussion stats
  • 2 replies
  • 738 views
  • 0 likes
  • 2 in conversation