hi all,
i have the dataset with variables id name joining date and salary
the birthdate is in the format date9.
now i have to read birthday only year i am trying with substr function but not getting the result.
can some one help me.
i tried as
x=substr("join_date"d, length("join_date"d)-3,4);
Is it correct?
Just use the year() function. If you need it as character, wrap it into put(year(join_date),4.);
Is your join date variable a character or number/sas date. If its a number then Kurts solution is correct. If its a char yours is close but need to remove quotes and d from around join_date variable. Its not a good method because what if the date is shorter in some circumstances though.
I agree with Reeza on the character. If its a date then you would normally have some kind of delimiter between day/month/year. Easier to check that:
for date_variable="01/JAN/2000"
Year=scan(date_variable,3,"/");
Should set year="2000" as its the third part.
Hi there, I'm moving this from the "about Communities on SAS" space to the SAS Procedures space just so that these answers are visible to others in that area. Thanks!
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