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Ravikumarkummari
Quartz | Level 8

hi all,

i have the dataset with variables id name joining date and salary

the birthdate is in the format date9.

now i have to read birthday only year i am trying with substr function but not getting the result.

can some one help me.

i tried as

x=substr("join_date"d, length("join_date"d)-3,4);

Is it correct?

4 REPLIES 4
Reeza
Super User

Is your join date variable a character or number/sas date. If its a number then Kurts solution is correct. If its a char yours is close but need to remove quotes and d from around join_date variable. Its not a good method because what if the date is shorter in some circumstances though.

RW9
Diamond | Level 26 RW9
Diamond | Level 26

I agree with Reeza on the character.  If its a date then you would normally have some kind of delimiter between day/month/year.  Easier to check that:

for date_variable="01/JAN/2000"

Year=scan(date_variable,3,"/");

Should set year="2000" as its the third part.

Community_Help
SAS Employee

Hi there, I'm moving this from the "about Communities on SAS" space to the SAS Procedures space just so that these answers are visible to others in that area. Thanks!

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