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Tim123
Calcite | Level 5

I am trying to output natural numbers that are not divisible by 3 and 5 on SAS data step.

data x;

k=0;

a=0;

do until(k>=70);

output;

a= Mod(k,3)~=0 and a= Mod(k,5)~=0;

k=k+1;

end;

drop k;

run;

This is obviously not correct!

2 REPLIES 2
ballardw
Super User

Maybe a tad simplier:

data want;

     do a=0 to 100;

     if mod(a,3) ne 0 and mod(a,5) ne 0 then output;

     end;

run;

    

Your a= Mod(k,3)~=0 and a= Mod(k,5)~=0; was assigning a logical value to A based on comparing the first mod to 0 which yields a 0 or 1 depending true, then comparing the current value of a to mod(k,5) and then the 0. Since the logical comparisons always yield 0 or 1 in SAS terms you weren't getting what you want. And the specific operations generally result in False

PGStats
Opal | Level 21

You weren't that far :

data x;

do k = 0 to 70;

    if Mod(k, 3) ~= 0 and Mod(k, 5) ~= 0 then output;

    end;

run;

PG

PG

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