I am trying to output natural numbers that are not divisible by 3 and 5 on SAS data step.
data x;
k=0;
a=0;
do until(k>=70);
output;
a= Mod(k,3)~=0 and a= Mod(k,5)~=0;
k=k+1;
end;
drop k;
run;
This is obviously not correct!
Maybe a tad simplier:
data want;
do a=0 to 100;
if mod(a,3) ne 0 and mod(a,5) ne 0 then output;
end;
run;
Your a= Mod(k,3)~=0 and a= Mod(k,5)~=0; was assigning a logical value to A based on comparing the first mod to 0 which yields a 0 or 1 depending true, then comparing the current value of a to mod(k,5) and then the 0. Since the logical comparisons always yield 0 or 1 in SAS terms you weren't getting what you want. And the specific operations generally result in False
You weren't that far :
data x;
do k = 0 to 70;
if Mod(k, 3) ~= 0 and Mod(k, 5) ~= 0 then output;
end;
run;
PG
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