I am trying to output natural numbers that are not divisible by 3 and 5 on SAS data step.
data x;
k=0;
a=0;
do until(k>=70);
output;
a= Mod(k,3)~=0 and a= Mod(k,5)~=0;
k=k+1;
end;
drop k;
run;
This is obviously not correct!
Maybe a tad simplier:
data want;
do a=0 to 100;
if mod(a,3) ne 0 and mod(a,5) ne 0 then output;
end;
run;
Your a= Mod(k,3)~=0 and a= Mod(k,5)~=0; was assigning a logical value to A based on comparing the first mod to 0 which yields a 0 or 1 depending true, then comparing the current value of a to mod(k,5) and then the 0. Since the logical comparisons always yield 0 or 1 in SAS terms you weren't getting what you want. And the specific operations generally result in False
You weren't that far :
data x;
do k = 0 to 70;
if Mod(k, 3) ~= 0 and Mod(k, 5) ~= 0 then output;
end;
run;
PG
Are you ready for the spotlight? We're accepting content ideas for SAS Innovate 2025 to be held May 6-9 in Orlando, FL. The call is open until September 16. Read more here about why you should contribute and what is in it for you!
Learn the difference between classical and Bayesian statistical approaches and see a few PROC examples to perform Bayesian analysis in this video.
Find more tutorials on the SAS Users YouTube channel.
Select SAS Training centers are offering in-person courses. View upcoming courses for: