I will consider sending a ticket to support later today. Seeing others not being able to replicate these results is making me doubt my own sanity lol. But otherwise, for funsies, happy to oblige with some experiments.   More subtractions:   Remove r = m-n   Replace value of n to 1/3 from 1/a (notice the sign change for r). This makes me thing that assigning a = 3 has some thing to do with this.   Lastly, outputting the values to log does fix the problem only if the values were written to log before r is calculated. Same thing but different order         ... View more

Hi,   I looked into this a bit further and it appears that be behavior I observed is unique to SAS 9.4_M6 (as others already commented that they can't replicate on other version).  I rerun the same code on with 9.4_M7 and I got the expected behavior (the difference is 0).   More specifically, in 9.4_M6, I have this behavior (I promise this is a different screenshot from before, I just rerun the thing again):   The same code with 9.4_M7: ... View more

Hi Quentin,   Yes, I did restart my computer (just in case), restart the session, tried in both SAS 9.4 and SAS EG, I still have the same result that I posted earlier. I wonder if it's because I am running on a slightly older version of SAS (9.4_M6) since other people can't replicate what I see (except OP since we are having the same results).   Best ... View more

Hi, After running proc product_status, it seems that my version is 9.4_M6 with image version 9.04.01M6P110718 ... View more

Hi,   Do you mind if I ask further clarification question? Because it seems that this goes beyond the precision issue. If 1/3 cannot be represented precisely in binary, shouldn't the value of c and d be BOTH off by the same amount and their difference should be zero regardless?   I tried rerun the code and it seems that simply outputting the results to the log using put (as seen on my post above) would change the result of r and s. This seems too unintuitive for me to be explain by the numeric precision issue. ... View more

Hi Tom, I reran the same code and got the result that the OP had.     However, if I insert the "put" command in between, suddenly both are 0 again. But outputting the values to log shouldn't change the calculation, should it?     Best,     ... View more