Please I need help with the SAS code below that does not produce expected reuslt:   Consider the hospital Admit label “HOSP_ADMSN_TIME” is a character variable as below and the hospital discharge time “HOSP_DISCH_TIME” is a character variable as below, and compute the length of stay “LOS” using SAS. HOSP_ADMSN_TIME Char 17 $17. $17. HOSP_ADMSN_TIME HOSP_DISCH_TIME Char 17 $17. $17. HOSP_DISCH_TIME Example of the character data as in excel is as below HOSP_ADMSN_TIME HOSP_DISCH_TIME 2022-05-12 11:35:00 2022-05-21 15:46:00 2022-05-12 11:35:00 2022-05-21 15:46:00 2022-05-12 11:35:00 2022-05-21 15:46:00 2022-05-12 11:35:00 2022-05-21 15:46:00 2022-05-12 11:35:00 2022-05-21 15:46:00 2022-05-12 11:35:00 2022-05-21 15:46:00     I used the following code to compute length of stay but the result is wrong please help. data new_count;     set new_count;      /* Convert character HOSP_ADMSN_TIME to numeric datetime */     dt_HOSP_ADMSN_TIME = input(HOSP_ADMSN_TIME, anydtdtm19.);         /* Convert character HOSP_DISCH_TIME to numeric datetime */     dt_HOSP_DISCH_TIME = input(HOSP_DISCH_TIME, anydtdtm19.);         /* Calculate the Length of Stay (LOS) in days */     LOS = (dt_HOSP_DISCH_TIME - dt_HOSP_ADMSN_TIME) / (60*60*24); /* Convert seconds to days */         /* Format the datetime variables for readability */     format dt_HOSP_ADMSN_TIME datetime19. dt_HOSP_DISCH_TIME datetime19.;         /* Drop the original character variables if not needed */     drop HOSP_ADMSN_TIME HOSP_DISCH_TIME;         /* Rename the new datetime variables to the original names */     rename dt_HOSP_ADMSN_TIME = HOSP_ADMSN_TIME            dt_HOSP_DISCH_TIME = HOSP_DISCH_TIME; run; ... View more