Thanks, it work ... View more

I finally figure it out, this is what I wrote; t=InverseC[(loc(InverseC^=0))]; print t;       tt=t(t); print tt;     Big=SurvivalM*(tt);        print Big; Putting everything on the same lile does not work ... View more

I created this matrix BIG ROW1 0 0 1.0875421 0 0 0 0 0 0 0 0 0 0 0 0 4.1015873 0 0 0 0 ROW2 0 0 1.030303 0 0 0 0 0 0 0 0 0 0 0 0 3.8857143 0 0 0 0 ROW3 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 3.7714286 0 0 0 0 ROW4 0 0 0.969697 0 0 0 0 0 0 0 0 0 0 0 0 3.6571429 0 0 0 0 ROW5 0 0 0.9090909 0 0 0 0 0 0 0 0 0 0 0 0 3.4285714 0 0 0 0 ROW6 0 0 0.8484848 0 0 0 0 0 0 0 0 0 0 0 0 3.2 0 0 0 0 ROW7 0 0 0.7878788 0 0 0 0 0 0 0 0 0 0 0 0 2.9714286 0 0 0 0 ROW8 0 0 0.7272727 0 0 0 0 0 0 0 0 0 0 0 0 2.7428571 0 0 0 0 ROW9 0 0 0.6666667 0 0 0 0 0 0 0 0 0 0 0 0 2.5142857 0 0 0 0 ROW10 0 0 0.6060606 0 0 0 0 0 0 0 0 0 0 0 0 2.2857143 0 0 0 0 ROW11 0 0 0.5454545 0 0 0 0 0 0 0 0 0 0 0 0 2.0571429 0 0 0 0 ROW12 0 0 0.4848485 0 0 0 0 0 0 0 0 0 0 0 0 1.8285714 0 0 0 0 ROW13 0 0 0.4242424 0 0 0 0 0 0 0 0 0 0 0 0 1.6 0 0 0 0 ROW14 0 0 0.3636364 0 0 0 0 0 0 0 0 0 0 0 0 1.3714286 0 0 0 0 ROW15 0 0 0.3030303 0 0 0 0 0 0 0 0 0 0 0 0 1.1428571 0 0 0 0 ROW16 0 0 0.2651515 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 ROW17 0 0 0.2272727 0 0 0 0 0 0 0 0 0 0 0 0 0.8571429 0 0 0 0 ROW18 0 0 0.1515152 0 0 0 0 0 0 0 0 0 0 0 0 0.5714286 0 0 0 0 ROW19 0 0 0.0757576 0 0 0 0 0 0 0 0 0 0 0 0 0.2857143 0 0 0 0 ROW20 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 and want to create another matrix BIGG by deleting all the colums that have first element equal zero in BIG to produce the matrix BIGG. This is the wrong code; SurvivalM=J(nrow(survival1),1,1);               do i = 1 to n;                 if censored=1 then SurvivalM=survival1; else if censored[1]=0 then SurvivalM=survival1;  /*****Create a 1 by N -matrix of Survival ****/;             end;           print SurvivalM;     InverseC=J(nrow(survival1),1,1);           do i = 1 to n;       if censored=1 then InverseC=1/survival1; else if censored[1]=0 then InverseC=0;  /*****survivalC is the imputed censored survival and set the real Survivalval to 1**/;          *InverseCC=J(nrow(survival1),1,1); end;       print InverseC; Big=SurvivalM*t(InverseC); print BIG; /*** for this code I want to delete all colums of BIG where row1 and col1 are zero ***/; BIGG=J(nrow(BIGG),20,1); do 1 to n; if col[i,1]=0 then delete; end; print BIGG; statement : ASSIGN at line 4338 column 1 4339  do 1 to n;          -          22          200 ERROR 22-322: Syntax error, expecting one of the following: a name, ;, DATA, UNTIL, WHILE. ERROR 200-322: The symbol is not recognized and will be ignored. 4340  if col[i,1]=0 then delete; 4341  end; ERROR: END does not occur within DO group at line=4341 col=1. 4342  print BIGG; ERROR: Matrix BIGG has not been set to a value. statement : PRINT at line 4342 column 1 ... View more

Thanks, do you know how to delete rows within proc iml. I created this matrix in proc iml and want to delete the rows of 1s ... View more

Thanks, what do I do if I want the the columns to be V1, V2, V3 , without skippying numbers ... View more

THis is the error message;   print InverseC ; 3218 m=frequency[1]; 3219 t = j(nrow(InverseC),1,1); 3220 t=loc(InverseC^=1); 3221 Big=SurvivalM*t(t)   ERROR: (execution) Matrices do not conform to the operation. operation : *` at line 3221 column 20 operands : SurvivalM, t SurvivalM 20 rows 1 col (numeric) t 1 row 3 cols (numeric) 14 16 20 statement : ASSIGN at line 3221 column 7 3222 print Big; It clearly state SurvivalM 20 rows 1 col (numeric) and t 1 row 3 cols (numeric) How comes it does not give me a 20X3 matrix. ??? ... View more

It does not work, this are my two matrices. The fisrt is 20X1 and the second is 20X1;. Once I delete all 1s in the second, suppose to be 3X1, then transpose to have 1X3. THus 20X1 multiply 1X3=20X3 0.95 0.9 0.85 0.8 0.75 0.7 0.65 0.6 0.55 0.5 0.45 0.4 0.35 0.3208333 0.2916667 0.2552083 0.21875 0.1458333 0.0729167 0.0729167   1 1 1 1 1 1 1 1 1 1 1 1 1 3.1168831 1 3.9183673 1 1 1 13.714286 ... View more