Dear,
In my data, the date time variable has the below values. I am using anydtdtm. informat to convert char to numeric, but it is working only for 2nd obs. Which informat should i use to output both rows. Thank you.
data have; input dtm $19.; datalines; 2016-06-02T14:44 2016-04-08 ; data want; set have; ndtm=input(dtm,anydtdtm.); format ndtm datetime18.; run;
Hello Kn,
I'm not sure which informat needed in this case . But here is an solutions , which may help to fulfill your request .
data want;
set have;
st=compress(substr(scan(dtm,3,'-'),3,1));
if st eq 'T' then dtm_ = substr(dtm,1,10);
else dtm_ =dtm;
ndtm=input(dtm_,anydtdte12.);
format ndtm date9.;
drop dtm_ st;
run;
Thanks...
You need to be selective with respect to the length of dtm:
data have;
input dtm $19.;
datalines;
2016-06-02T14:44
2016-04-08
;
run;
data want;
set have;
if length(dtm) = 10
then mydtm = dhms(input(dtm,e8601da10.),0,0,0);
else mydtm = input(dtm,e8601dt19.);
format mydtm e8601dt19.;
run;
Note that the informat E8601DA10. is equivalent to YYMMDD10.
It's finally time to hack! Remember to visit the SAS Hacker's Hub regularly for news and updates.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.
Ready to level-up your skills? Choose your own adventure.