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thanikondharish
Fluorite | Level 6
%let name=ABCD efgh,ijkl mnop,qrst;

%put. %scan(&name,1, ,);


How to derive first delimiter string see below..

ABCD efgh


4 REPLIES 4
Patrick
Opal | Level 21

%let name=ABCD efgh,ijkl mnop,qrst;
%put %scan(%nrbquote(&name),1,%nrbquote(,));

Ksharp
Super User
%let name=ABCD efgh,ijkl mnop,qrst;

%put %scan(%bquote(&name),1,%(,));
Quentin
Super User

@Ksharp I think you're missing the STR.  As written:

%scan(%bquote(&name),1,%(,));

would treat four characters as delimiters: % ( )  ,

It works because the () are enough to hide the comma from the macro processor during the macro call.  But if the string has % or () in it, those characters will be delimiters.

 

1 %let name=ABCD% ef(gh,ijkl m)nop,qrst;
2 %put %scan(%bquote(&name),1,%(,));
ABCD

But with %STR(), it treats only one character as a delimiter: ,

 

3 %put %scan(%bquote(&name),1,%str(,));
ABCD% ef(gh

 

 

Ksharp
Super User

Yeah. I am sure I write %STR ,

%put %scan(%bquote(&name),1,%str(,));

But I don't know why it would appear this. Maybe this forum eat 'STR' .

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