BookmarkSubscribeRSS Feed
🔒 This topic is solved and locked. Need further help from the community? Please sign in and ask a new question.
twildone
Pyrite | Level 9

Hi...Is there something similiar or equivalent to holiday('labor', year) but rather than producing the first Monday in September, the result would the first Monday in August? Thnaks.

1 ACCEPTED SOLUTION

Accepted Solutions
mohamed_zaki
Barite | Level 11
data null;
year=2016;
month=8;
format monday date9.;
monday=intnx('week.3',(mdy(month,1,year)),0,'e');
run;

View solution in original post

4 REPLIES 4
mohamed_zaki
Barite | Level 11
data null;
year=2016;
month=8;
format monday date9.;
monday=intnx('week.3',(mdy(month,1,year)),0,'e');
run;
advoss
Quartz | Level 8

If you are looking for the same day, one month prior to Labor day, you can do:

data _null_;

 date_labor = holiday('LABOR',year(today()));

 date_1MonthPrior = intnx('MONTH',date_labor,-1,'S');

 format Date_: YYMMDD10.;

 put _all_;

 stop;

run;

date_labor=2016-09-05 date_1MonthPrior=2016-08-05 _ERROR_=0 _N_=1

 

Ksharp
Super User
data _null_;
x=NWKDOM(1, 2, 8, 2016);
put x= date9.;
run;

Ready to join fellow brilliant minds for the SAS Hackathon?

Build your skills. Make connections. Enjoy creative freedom. Maybe change the world. Registration is now open through August 30th. Visit the SAS Hackathon homepage.

Register today!
How to Concatenate Values

Learn how use the CAT functions in SAS to join values from multiple variables into a single value.

Find more tutorials on the SAS Users YouTube channel.

Click image to register for webinarClick image to register for webinar

Classroom Training Available!

Select SAS Training centers are offering in-person courses. View upcoming courses for:

View all other training opportunities.

Discussion stats
  • 4 replies
  • 1126 views
  • 0 likes
  • 4 in conversation