Hi...Is there something similiar or equivalent to holiday('labor', year) but rather than producing the first Monday in September, the result would the first Monday in August? Thnaks.
data null;
year=2016;
month=8;
format monday date9.;
monday=intnx('week.3',(mdy(month,1,year)),0,'e');
run;
data null;
year=2016;
month=8;
format monday date9.;
monday=intnx('week.3',(mdy(month,1,year)),0,'e');
run;
If you are looking for the same day, one month prior to Labor day, you can do:
data _null_;
date_labor = holiday('LABOR',year(today()));
date_1MonthPrior = intnx('MONTH',date_labor,-1,'S');
format Date_: YYMMDD10.;
put _all_;
stop;
run;
date_labor=2016-09-05 date_1MonthPrior=2016-08-05 _ERROR_=0 _N_=1
data _null_;
x=NWKDOM(1, 2, 8, 2016);
put x= date9.;
run;
April 27 – 30 | Gaylord Texan | Grapevine, Texas
Walk in ready to learn. Walk out ready to deliver. This is the data and AI conference you can't afford to miss.
Register now and save with the early bird rate—just $795!
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.
Ready to level-up your skills? Choose your own adventure.