Could someone kindly tell me what this regular expression "(prxmatch(/[#]/,&path.))=0" means?
%if %sysfunc(prxmatch(/[#]/,&path.))=0 %then %do;
with a concrete case will be better.thank you for your time
Hello,
I would say that the square brackets here are useless and the regex is only used to
test whether the path macrovariable contains a hash sign.
234 %macro regexp(path);
235 %if %sysfunc(prxmatch(/[#]/,&path.))=0 %then %do;
236 %put OK;
237 %end;
238 %else %do;
239 %put KO;
240 %end;
241 %mend;
242
243 %regexp(c:/temp);
OK
244 %regexp(c:/temp/file#1);
KO
[list of characters] matches any character in the list.
Hello,
I would say that the square brackets here are useless and the regex is only used to
test whether the path macrovariable contains a hash sign.
234 %macro regexp(path);
235 %if %sysfunc(prxmatch(/[#]/,&path.))=0 %then %do;
236 %put OK;
237 %end;
238 %else %do;
239 %put KO;
240 %end;
241 %mend;
242
243 %regexp(c:/temp);
OK
244 %regexp(c:/temp/file#1);
KO
[list of characters] matches any character in the list.
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