prxmatch(/[#]/,&path.)=0

[ccnky123]

Could someone kindly tell me what this regular expression "(prxmatch(/[#]/,&path.))=0" means?

%if %sysfunc(prxmatch(/[#]/,&path.))=0 %then %do;

with a concrete case will be better.thank you for your time

[gamotte · Accepted solution]

Hello,

I would say that the square brackets here are useless and the regex is only used to

test whether the path macrovariable contains a hash sign.

234  %macro regexp(path);
235  %if %sysfunc(prxmatch(/[#]/,&path.))=0 %then %do;
236     %put OK;
237  %end;
238  %else %do;
239     %put KO;
240  %end;
241  %mend;
242
243  %regexp(c:/temp);
OK
244  %regexp(c:/temp/file#1);
KO

[list of characters] matches any character in the list.