Thanks! it works if the date variable was treated ad in DATETIME value.
qtr(datepart(datetime_value))
Pieces of code work before, but don't work now. The data test from SQL server and imported in csv format; test is subset of csv, containing 2 rows.
mif_data_reporting_dt is numeric in datetime 16 format. Attached test table and error message. Thanks in advance!
proc import out=csv
datafile="F:\Shared\CMIP\Run81_sas_in.txt"
dbms=csv replace;
getnames=Yes;
run;
data new_data; set test; rptqtr=qtr(mif_data_reporting_dt); rptyr=year(mif_data_reporting_dt); run;
I don't understand.
Why are you creating dataset CSV in the first step and then reading from dataset TEST in the second step?
If you have a CSV file then just write a data step to read it and you will have full control over how the variables are defined.
1,972,252,800 is not a valid date value. With an average of 365.25 days per year that would be past the year 5 million.
734 data test; 735 date=1972252800 ; 736 year = 1960 + int(date/365.25); 737 738 put date=comma32. year=comma32. ; 739 put date=datetime20.; 740 run; date=1,972,252,800 year=5,401,693 date=01JUL2022:00:00:00
Probably your variable is actually a DATETIME value instead of a DATE value. To find a QUARTER from a DATETIME value first convert the number of seconds to number of days.
qtr(datepart(datetime_value))
Thanks! it works if the date variable was treated ad in DATETIME value.
qtr(datepart(datetime_value))
It's finally time to hack! Remember to visit the SAS Hacker's Hub regularly for news and updates.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.
Ready to level-up your skills? Choose your own adventure.