Thanks! it works if the date variable was treated ad in DATETIME value.
qtr(datepart(datetime_value))
Pieces of code work before, but don't work now. The data test from SQL server and imported in csv format; test is subset of csv, containing 2 rows.
mif_data_reporting_dt is numeric in datetime 16 format. Attached test table and error message. Thanks in advance!
proc import out=csv
datafile="F:\Shared\CMIP\Run81_sas_in.txt"
dbms=csv replace;
getnames=Yes;
run;
data new_data; set test; rptqtr=qtr(mif_data_reporting_dt); rptyr=year(mif_data_reporting_dt); run;
I don't understand.
Why are you creating dataset CSV in the first step and then reading from dataset TEST in the second step?
If you have a CSV file then just write a data step to read it and you will have full control over how the variables are defined.
1,972,252,800 is not a valid date value. With an average of 365.25 days per year that would be past the year 5 million.
734 data test; 735 date=1972252800 ; 736 year = 1960 + int(date/365.25); 737 738 put date=comma32. year=comma32. ; 739 put date=datetime20.; 740 run; date=1,972,252,800 year=5,401,693 date=01JUL2022:00:00:00
Probably your variable is actually a DATETIME value instead of a DATE value. To find a QUARTER from a DATETIME value first convert the number of seconds to number of days.
qtr(datepart(datetime_value))
Thanks! it works if the date variable was treated ad in DATETIME value.
qtr(datepart(datetime_value))
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