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Anthony_eng
Obsidian | Level 7

One of my variables is made up of long strings.  Similar to the following:

 

CODE

01|02|03|04|07|0A|0B|0C

01|02|03|04|05|0A|0B

 

I have tried using % wildcard operator, which works in SQL, but I couldn't get it to work in SAS.  I also tried using * which I had seen used in another similar question.  I would like to use an IF THEN statement to do the following:

 

IF  CODE CONTAINS '03' THEN DO;

 

Unfortunately only arithmetic operators can be used with IF THEN statements.  I considered using the SUBSTR function, but I don't know the starting position of the codes, they can change for each observation.  Any advice or ideas on how I can solve this issue?

1 ACCEPTED SOLUTION

Accepted Solutions
PaigeMiller
Diamond | Level 26
if find(code,'03') then do;
--
Paige Miller

View solution in original post

3 REPLIES 3
PaigeMiller
Diamond | Level 26
if find(code,'03') then do;
--
Paige Miller
AMSAS
SAS Super FREQ

The wildcards only work with WHERE statements 

 

Take a look at PRXMATCH Function, and the examples

Reeza
Super User

@Anthony_eng wrote:

One of my variables is made up of long strings.  Similar to the following:

 

CODE

01|02|03|04|07|0A|0B|0C

01|02|03|04|05|0A|0B

 

I have tried using % wildcard operator, which works in SQL, but I couldn't get it to work in SAS.  I also tried using * which I had seen used in another similar question.  I would like to use an IF THEN statement to do the following:

 

IF  CODE CONTAINS '03' THEN DO;

 

Unfortunately only arithmetic operators can be used with IF THEN statements.  I considered using the SUBSTR function, but I don't know the starting position of the codes, they can change for each observation.  Any advice or ideas on how I can solve this issue?


INDEXW/FINDW are functions you'll want. 

FIND will find 01 within 001. 

 

I think the statement in purple contradicts itself, not sure why you think "only arithmetic operators can be used with IF THEN statements". 

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