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genemroz
Quartz | Level 8

Esteemed Advisers;

I'm trying to import a csv file with datetime data in the following format:

yyyy-mm-dd hh:mm:ss UTC

I can't find an informat that works and need some advice on how to proceed. 

Below is a sample of what I've tried but isn't working--(thanks in advance!):

 data have;
 /*INFORMAT*/
 informat created_at $19.;
 /*FORMAT*/
 format created_UTC datetime16. ;
 /**/
 input
 created_at
 ;
 datalines;
 2022-04-01 00:01:20 UTC
 2022-04-01 00:03:20 UTC
 2022-04-01 00:05:20 UTC
 run;
 
data want
created_UTC
01APR22:00:01:20
01APR22:00:03:20
01APR22:00:04:20
1 ACCEPTED SOLUTION

Accepted Solutions
Tom
Super User Tom
Super User

You cannot use a numeric format with a character variable.  In particular to use the DATETIME format to display a variable it needs to be a numeric variable with datetime values (number of seconds since 1960).

So if you have this data:

data have;
  input created_at $23.;
datalines;
2022-04-01 00:01:20 UTC
2022-04-01 00:03:20 UTC
2022-04-01 00:05:20 UTC
;

You can try to convert it to a datetime value by ignoring the timezone.  You could then use the TZONEOFF() function to try to adjust to a different timezone if you want.

data want;
  set have;
  dt = input(created_at,anydtdtm19.);
  timezone = scan(created_at,-1,' ');
  offset = tzoneoff(timezone);
  local_offset = tzoneoff();
  local_dt = dt - offset + local_offset;
  format dt local_dt datetime19. offset local_offset time6.;
run;

Results:

Tom_0-1653674746994.png

 

 

View solution in original post

5 REPLIES 5
yabwon
Onyx | Level 15
data have;
format created_at datetime21. ;
input
 created_at ANYDTDTM19.
;
datalines;
2022-04-01 00:01:20 UTC
2022-04-01 00:03:20 UTC
2022-04-01 00:05:20 UTC
run;
proc print;
run;
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Tom
Super User Tom
Super User

You cannot use a numeric format with a character variable.  In particular to use the DATETIME format to display a variable it needs to be a numeric variable with datetime values (number of seconds since 1960).

So if you have this data:

data have;
  input created_at $23.;
datalines;
2022-04-01 00:01:20 UTC
2022-04-01 00:03:20 UTC
2022-04-01 00:05:20 UTC
;

You can try to convert it to a datetime value by ignoring the timezone.  You could then use the TZONEOFF() function to try to adjust to a different timezone if you want.

data want;
  set have;
  dt = input(created_at,anydtdtm19.);
  timezone = scan(created_at,-1,' ');
  offset = tzoneoff(timezone);
  local_offset = tzoneoff();
  local_dt = dt - offset + local_offset;
  format dt local_dt datetime19. offset local_offset time6.;
run;

Results:

Tom_0-1653674746994.png

 

 

genemroz
Quartz | Level 8

Tom:

 

Thanks for the quick response.  I tried your code but am not getting the result that you show.  Namely, the dt and local_dt variable columns are empty.  My code is below:

data have;
input created_at $23.;
datalines;
2022-04-01 00:01:20 UTC
2022-04-01 00:03:20 UTC
2022-04-01 00:05:20 UTC
run;

data want;
set have;
dt=input(created_at,anytdtdtm19.);
timezone=scan(created_at,-1,' ');
offset=tzoneoff(timezone); 
local_offset=tzoneoff();
local_dt=dt - offset + local_offset;
format dt local_dt datetime19. offset local_offset time6.;
run;
proc print;
run;
Tom
Super User Tom
Super User

An extra T got inserted into the informat name in the INPUT() function call.

1421  set have;
1422  dt=input(created_at,anytdtdtm19.);
                          ------------
                          48
ERROR 48-59: The informat ANYTDTDTM was not found or could not be loaded.

ANYDTDTM is the name of the informat.

 

If the extra T is not in your code then change that the spaces in CREATED_AT are actually spaces and not tabs ('09'x) or non-breaking spaces ('A0'x) or some other invisible character.

genemroz
Quartz | Level 8
Ahh, yes, typos rear their ugly head again. Thanks for this solution. I'm marking it as Accepted.

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