data mydate (keep=ln_no mydate);
set date1;
run;
output is
ln_no mydate
011 09JUN2015:00:00:00.000
I tried using this
newdt = datepart(mydate);
format newdt mmddyy10.
For some reason the newdt turns into a numeric and looses its date datatype.
I want to extract the 09JUN2015 since the datepart function on this particular field does not convert to a date.
For some reason the newdt turns into a numeric and looses its date datatype.
SAS Dates, times and datetimes are stored as numeric variables.
Is your starting variable a numeric variable with a datetime format?
If it's character, DATEPART() will not work. In that case, you can use SCAN instead with the : as the delimiter and then use INPUT to convert it to a SAS date.
It seems that the variable MYDATE is a char type - that is a character string,
then you can read it either by defining its length $9 with informat date9. (neglect the time part)
or if you have it as one char type variable of length $24 then:
datex = scan(mydate,1,':');
date = input(datex,date9.);
format date date9.;
Great info,it worked!!
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