Extract date only from datetime format

[Q1983]

data mydate (keep=ln_no mydate);

set date1;

run;

output is

ln_no    mydate

011     09JUN2015:00:00:00.000

I tried using this
newdt = datepart(mydate);

format newdt mmddyy10.

For some reason the newdt turns into a numeric and looses its date datatype.

I want to extract the 09JUN2015 since the datepart function on this particular field does not convert to a date.

[Reeza]

For some reason the newdt turns into a numeric and looses its date datatype.

SAS Dates, times and datetimes are stored as numeric variables. 

Is your starting variable a numeric variable with a datetime format?

If it's character, DATEPART() will not work. In that case, you can use SCAN instead with the : as the delimiter and then use INPUT to convert it to a SAS date. 

[Shmuel]

It seems that the variable MYDATE is a char type - that is a character string, 

then you can read it either by defining its length $9 with informat date9. (neglect the time part)

or if you have it as one char type variable of length $24 then:

     datex = scan(mydate,1,':');

     date = input(datex,date9.);

     format date date9.;

[shindekiranp]

Great info,it worked!!