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phadnismukta
Fluorite | Level 6

Hello,  

 

I am creating a CSV file using a big SAS dataset. I need to zip the CSV file in multiple smaller zip file.

Can it be done using filename statement?

I need something similar to

zip -s 1000m SPLIT_FILES small_FILE.ZIP

 

Thanks.

 

2 REPLIES 2
ChrisNZ
Tourmaline | Level 20

The FILENAME statement will not do this.

You can either run a system command to split the zip file afterward, something like

zip existing.zip --out new.zip -s 50m

or create several independent files with FILENAME. 

yabwon
Amethyst | Level 16

Hi,

 

Maybe something like this will help:

data have;
do i = 1 to 100;
  x = "ABC";
  output;
end;
run;


%let directory = %sysfunc(pathname(work)); /* put the directory you want to store files here */
%put *&=directory.*;

/*options mprint;*/
%macro split2zips(data,variables,directory,parts=5);
data _null_;
  call symputX("size",ceil(nobs/&parts.),"L"); 
  stop;
  set &data. nobs=nobs;
run;

%local I;
%do I = 1 %to &parts.;

FILENAME F ZIP "&directory./file_no&I..zip" MEMBER = "file_no&I..csv" Lrecl = 1024; 
data _null_;
  FILE F;
  SET &data.(
      keep = &variables. 
      firstobs = %sysevalf((&I.-1)*&size. + 1) 
      obs      = %sysevalf(&I.*&size.)
      );
  PUT "&I." (_ALL_) (","); /*adjust to your needs*/
run; 
FILENAME F;
%end;


%mend split2zips;

%split2zips(have, i x, &directory.)

 

All the best

Bart

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