Counting row by group through proc sql

[V_R]

Hi,

How can i add count rows by groups through proc sql

Have dataset

x y

1 a

1 b

1 c

2 g

2 p

3 f

wanted output 

x y n

1 a 1

1 b 2

1 c 3

2 g 1

2 p 2

3 f 1

Grouping variable is x

i know  how to do it with data step

Proc sort data = have ; 

by x;

run;

data want;

set have;

by x;

if first.x then N =1;

else N+1;

run;

However i am finding equivalent code in Proc SQL. 

"row_number() over partition by " does not work in proc sql

[Patrick]

With SQL use a Group By clause. Looking at your sample data/desired result: What's the grouping variable? Why is n=1 for 1a but n=2 for 1b? If the grouping variable would be X then n should be 3 for the first 3 rows, if it's Y then it should be 1 for all rows.

[V_R]

Grouping variable is x

[Patrick]

The data step you've posted is not really implementing a count by group but it's just counting up and you reset the count by group. There is not really something equivalent in ANSI SQL (many databases have extensions ANSI SQL - analytic functions - which allow for similar things).

With ANSI SQL you can have a count by group - but that works against sets of rows and not sequentially like with a SAS data step (compare the differences returned by below code).

Once you understand the differences between a SAS data step and SQL you can take full advantage of it and use whatever you need.

data have;
  input x y $;
  datalines;
1 a
1 b
1 c
2 g
2 p
3 f
;
proc print;
run;

data want;
  set have;
  by x;
  if first.x then
    N =1;
  else N+1;
run;
proc print;
run;

proc sql;
  select x, y, count(*) as n
  from have
  group by x
  ;
quit;

[V_R]

For sql part 

output with your code is

x y n1 a 3
1 b 3
1 c 3
2 g 2
2 p 2
3 f 1 

what i want is 
x y n1 a 1
1 b 2
1 c 3
2 g 1
2 p 2
3 f 1

[Patrick]

That's what I've tried to tell you: Use a SAS data step for such a use case, use SAS SQL for a group count. Take advantage of the differences between the SAS data step and SQL.

[Kurt_Bremser]

As you see, it is very simple in a data step. Maxim 14: Use the Right Tool.

Stay with the data step.

[ChrisNZ]

> However i am finding equivalent code in Proc SQL.

SQL is not very suited to processing rows in a given order.

A data step is.

> "row_number() over partition by " does not work

This non-ANSI feature is not implemented in SAS. Time to vote.

[novinosrin · Accepted solution]

HI @V_R   These kind of questions seems more of university fun puzzles rather than a practical application in industry. How I wish I can reverse the clock and go back to Uni. I am missing those days at the lab.

The idea is to use MONOTONIC() and RANK by GROUP. 

data have;
  input x y $;
  datalines;
1 a
1 b
1 c
2 g
2 p
3 f
;
proc sql;
create table want as
select a.x,a.y,count(b.m) as n
from (select *,monotonic() as m from have) a
left join 
(select *,monotonic() as m from have) b
on a.x=b.x and b.m<=a.m
group by a.x,a.y
order by a.x,n;
quit;

[jmann132]

You'd be surprised-- I came to this thread looking for a solution to this as a SAS user doing data analytics for business! Needed to randomly select X number of observations from each value of the grouped variable, with X being variable depending on the value. Idea being to evenly distribute the control group to with the other group based on this variable. So I randomly ordered my members in the group, and then needed to label them to prepare for selection. So your solution does have real-world value 🙂