Hi All:
Quick question: I have a 19 byte character field that contains only '0's and '1's. Is there a quick (simple) way to sum the numerals in the field
to see how many of them are set to '1'. This way if the sum is > 1 I know there is more than 1 byte not 'zero'. Unfortunately, the field is a
character field and I can't change that.
Thanks in advance.
data have;
input var $ 19.;
datalines;
0
0
1
1
0
1
0
0
;
data want(keep=cnt_one);
set have end=eof;
if strip(var)='1' then cnt_one+1;
if eof then output;
run;
Hi:
The data is in a variable formatted like: '0001001000110001000' and I basically need to count the number of '1's.
I could use an array but that is messy. Hoping for something simple.
Thanks.
ones = count(stringvar,'1');
should do it
Bingo - I knew there would be something simple!
Thanks.
It's finally time to hack! Remember to visit the SAS Hacker's Hub regularly for news and updates.
Learn the difference between classical and Bayesian statistical approaches and see a few PROC examples to perform Bayesian analysis in this video.
Find more tutorials on the SAS Users YouTube channel.
Ready to level-up your skills? Choose your own adventure.