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OS2Rules
Obsidian | Level 7

Hi All:

Quick question:  I have a 19 byte character field that contains only '0's and '1's.   Is there a quick (simple) way to sum the numerals in the field

to see how many of them are set to '1'.  This way if the sum is > 1 I know there is more than 1 byte not 'zero'.  Unfortunately, the field is a

character field and I can't change that.

Thanks in advance.

1 ACCEPTED SOLUTION

Accepted Solutions
ballardw
Super User

ones = count(stringvar,'1');

should do it

View solution in original post

4 REPLIES 4
stat_sas
Ammonite | Level 13

data have;
input var $ 19.;
datalines;
0
0
1
1
0
1
0
0
;

data want(keep=cnt_one);
set have end=eof;
if strip(var)='1' then cnt_one+1;
if eof then output;
run;

OS2Rules
Obsidian | Level 7

Hi:

The data is in a variable formatted like:  '0001001000110001000'   and I basically need to count the number of '1's.

I could use an array but that is messy.  Hoping for something simple.

Thanks.

ballardw
Super User

ones = count(stringvar,'1');

should do it

OS2Rules
Obsidian | Level 7

Bingo - I knew there would be something simple!

Thanks.

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