Hello,
How to create table like this one below. Sum first and second value and than from each value get rate. Is there anybody who know code for this problem?
My data
date | Value | E | D |
201612 | 82842 | 0 | 0 |
201612 | 621 | 0 | 1 |
201612 | 31595 | 1 | 0 |
201612 | 64 | 1 | 1 |
Want data
date | Value | E | D | Sum | Rate |
201612 | 82842 | 0 | 0 | 83463 | 0,74% |
201612 | 621 | 0 | 1 | ||
201612 | 31595 | 1 | 0 | 31659 | 0,20% |
201612 | 64 | 1 | 1 |
data have;
input date $ value e d;
cards;
201612 82842 0 0
201612 621 0 1
201612 31595 1 0
201612 64 1 1
;
run;
data want;
merge
have
have (firstobs=2 rename=(e=_e d=_d date=_date value=_value))
;
if d = 0 and _date = date and _e = e
then do;
sum = value + _value;
rate = _value / sum;
end;
format rate percent7.2;
keep date value e d sum rate;
run;
proc print data=want noobs;
run;
Result:
date value e d sum rate 201612 82842 0 0 83463 0.74% 201612 621 0 1 . . 201612 31595 1 0 31659 0.20% 201612 64 1 1 . .
data want;
merge
have
have (firstobs=2 rename=(e=_e d=_d date=_date value=_value))
;
if d = 0 and _date = date and _e = e
then do;
sum = value + _value;
rate = _value / sum;
end;
format rate percent7.2;
keep date value e d sum rate;
run;
Edit: added a closing bracket in the merge statement, to correct a syntax error.
This is result of this code...it doesnt work properly.
date | Value | E | D | Sum | Rate |
201612 | 621 | 0 | 0 | 1242 | 50.0% |
201612 | 31595 | 0 | 1 | . | . |
201612 | 64 | 1 | 0 | 128 | 50.0% |
201612 | 64 | 1 | 1 | . | . |
data have;
input date $ value e d;
cards;
201612 82842 0 0
201612 621 0 1
201612 31595 1 0
201612 64 1 1
;
run;
data want;
merge
have
have (firstobs=2 rename=(e=_e d=_d date=_date value=_value))
;
if d = 0 and _date = date and _e = e
then do;
sum = value + _value;
rate = _value / sum;
end;
format rate percent7.2;
keep date value e d sum rate;
run;
proc print data=want noobs;
run;
Result:
date value e d sum rate 201612 82842 0 0 83463 0.74% 201612 621 0 1 . . 201612 31595 1 0 31659 0.20% 201612 64 1 1 . .
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