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jopo12345678
Calcite | Level 5

Hello,

How to create table like this one below. Sum first and second value and than from each value get rate. Is there anybody who know code for this problem?

 

My data

 

dateValueED
2016128284200
20161262101
2016123159510
2016126411

 

Want data

 

dateValueEDSumRate
2016128284200834630,74%
20161262101  
2016123159510316590,20%
2016126411  
1 ACCEPTED SOLUTION

Accepted Solutions
Kurt_Bremser
Super User
data have;
input date $ value e d;
cards;
201612 82842 0 0
201612 621 0 1
201612 31595 1 0
201612 64 1 1
;
run;

data want;
merge
  have
  have (firstobs=2 rename=(e=_e d=_d date=_date value=_value))
;
if d = 0 and _date = date and _e = e
then do;
  sum = value + _value;
  rate = _value / sum;
end;
format rate percent7.2;
keep date value e d sum rate;
run;

proc print data=want noobs;
run;

Result:

 date     value    e    d     sum        rate

201612    82842    0    0    83463     0.74% 
201612      621    0    1        .      .    
201612    31595    1    0    31659     0.20% 
201612       64    1    1        .      .    

View solution in original post

3 REPLIES 3
Kurt_Bremser
Super User
data want;
merge
  have
  have (firstobs=2 rename=(e=_e d=_d date=_date value=_value))
;
if d = 0 and _date = date and _e = e
then do;
  sum = value + _value;
  rate = _value / sum;
end;
format rate percent7.2;
keep date value e d sum rate;
run;

Edit: added a closing bracket in the merge statement, to correct a syntax error.

jopo12345678
Calcite | Level 5

This is result of this code...it doesnt work properly.

dateValueEDSumRate
20161262100124250.0%
2016123159501..   
201612641012850.0%
2016126411..   
Kurt_Bremser
Super User
data have;
input date $ value e d;
cards;
201612 82842 0 0
201612 621 0 1
201612 31595 1 0
201612 64 1 1
;
run;

data want;
merge
  have
  have (firstobs=2 rename=(e=_e d=_d date=_date value=_value))
;
if d = 0 and _date = date and _e = e
then do;
  sum = value + _value;
  rate = _value / sum;
end;
format rate percent7.2;
keep date value e d sum rate;
run;

proc print data=want noobs;
run;

Result:

 date     value    e    d     sum        rate

201612    82842    0    0    83463     0.74% 
201612      621    0    1        .      .    
201612    31595    1    0    31659     0.20% 
201612       64    1    1        .      .    

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