Mean seperation procedures will not be carried out due to zero degrees of freedom for the specified error source. Using 9.4. Below is my setup in excel, attached is the sas output
Diet | Span | |||||
1 | 3.0 | 3.4 | 2.6 | 2.9 | 2.4 | |
2 | 2.8 | 3.3 | 3.6 | 3.5 | 3.4 | |
3 | 3.6 | 3.9 | 4.1 | 3.8 | 4.0 | |
Proc GLM;
class diet;
model span=diet;
means diet/lsd;
run;
Do you only have a single record for each diet?
Or are all the values in the row, values for span? If you haven't transposed the data then SAS will not be using all the span values, only the first one.
Do you only have a single record for each diet?
Or are all the values in the row, values for span? If you haven't transposed the data then SAS will not be using all the span values, only the first one.
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