Mean seperation procedures will not be carried out due to zero degrees of freedom for the specified error source. Using 9.4. Below is my setup in excel, attached is the sas output
Diet | Span | |||||
1 | 3.0 | 3.4 | 2.6 | 2.9 | 2.4 | |
2 | 2.8 | 3.3 | 3.6 | 3.5 | 3.4 | |
3 | 3.6 | 3.9 | 4.1 | 3.8 | 4.0 | |
Proc GLM;
class diet;
model span=diet;
means diet/lsd;
run;
Do you only have a single record for each diet?
Or are all the values in the row, values for span? If you haven't transposed the data then SAS will not be using all the span values, only the first one.
Do you only have a single record for each diet?
Or are all the values in the row, values for span? If you haven't transposed the data then SAS will not be using all the span values, only the first one.
Are you ready for the spotlight? We're accepting content ideas for SAS Innovate 2025 to be held May 6-9 in Orlando, FL. The call is open until September 25. Read more here about why you should contribute and what is in it for you!
Learn the difference between classical and Bayesian statistical approaches and see a few PROC examples to perform Bayesian analysis in this video.
Find more tutorials on the SAS Users YouTube channel.