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Boni
Calcite | Level 5

Hi,

I wonder if it is possible to retain the original identification (Here: unikdyr) from the dataset in the solution output from the random statement in PROC MIXED.

SAS code:

ods output solutionR=sol;

ods trace on;

PROC MIXED data=b covtest ratio;

     id unikdyr;

     model ekm = dimund60 dimov60 / s ddfm=bw outp=predicted;

     random dimund60 dimov60 int / type=un subject=unikdyr solution;

run;

odc trace off;

In the Solution output (sol) each individual now got a subject number, but I would like to be able to link that subjectnumber to an animalnumber (=unikdyr) because I want to use the random estimates in another model.

Any good ideas??

Thanks - Bodil

1 ACCEPTED SOLUTION

Accepted Solutions
SteveDenham
Jade | Level 19

Add a CLASS statement (I changed the ID statement to a CLASS statement, but you may need both for your outp= option statement):

PROC MIXED data=b covtest ratio;

     class unikdyr;

     model ekm = dimund60 dimov60 / s ddfm=bw outp=predicted;

     random dimund60 dimov60 int / type=un subject=unikdyr solution;

run;

The dataset sol should have what you are looking for.

Steve Denham

View solution in original post

2 REPLIES 2
SteveDenham
Jade | Level 19

Add a CLASS statement (I changed the ID statement to a CLASS statement, but you may need both for your outp= option statement):

PROC MIXED data=b covtest ratio;

     class unikdyr;

     model ekm = dimund60 dimov60 / s ddfm=bw outp=predicted;

     random dimund60 dimov60 int / type=un subject=unikdyr solution;

run;

The dataset sol should have what you are looking for.

Steve Denham

Boni
Calcite | Level 5

Thanks Steve!

How simple... Sometimes I tend to complicate things... ;o)

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