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Q1983
Lapis Lazuli | Level 10


proc sql;

create table test as

select ln,workout_trial_dt, my_cd

from table

where my_cd='c2';quit;

sample output

ln                       workout_trial_dt               my_cd

111                     02JAN2015                       c2

I need the date to show as the first day of the month.  In this case 01JAN2015

1 ACCEPTED SOLUTION

Accepted Solutions
data_null__
Jade | Level 19

You might consider the correct date interval.


data _null_;
   workout_trail_dt = today();
   wrong = intnx(
'day',workout_trail_dt,0,"BEGINNING");
   right = intnx(
'month',workout_trail_dt,0,"BEGINNING");
   put (_all_)(/=);
   format _all_ date9.;
  
run;

workout_trail_dt=
14MAY2015
wrong=
14MAY2015
right=
01MAY2015

View solution in original post

2 REPLIES 2
RW9
Diamond | Level 26 RW9
Diamond | Level 26

You can use the intnx function:

intnx('day',workout_trail_dt,0,"BEGINNING") as first_of_month.

data_null__
Jade | Level 19

You might consider the correct date interval.


data _null_;
   workout_trail_dt = today();
   wrong = intnx(
'day',workout_trail_dt,0,"BEGINNING");
   right = intnx(
'month',workout_trail_dt,0,"BEGINNING");
   put (_all_)(/=);
   format _all_ date9.;
  
run;

workout_trail_dt=
14MAY2015
wrong=
14MAY2015
right=
01MAY2015

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