how would i count distinct ID that are that have appointments after the next 28 days from today
ID appt_date
1 6/30/2018
1 7/7/2018
1 7/18/2018
1 7/28/2018
1 8/6/2018
1 9/20/2017
2 6/17/2018
2 6/28/2018
2 7/5/2018
2 7/6/2018
want
ID 1 has 4 appt after 28 days
ID 2 has 0 appt after 28 days
I think there are only 3 for ID1, are you sure it;s 4?
data have;
input ID appt_date :mmddyy10.;
format appt_date mmddyy10.;
cards;
1 6/30/2018
1 7/7/2018
1 7/18/2018
1 7/28/2018
1 8/6/2018
1 9/20/2017
2 6/17/2018
2 6/28/2018
2 7/5/2018
2 7/6/2018
;
proc sql;
create table want as
select id, sum( appt_date>=intnx('days',today(),28)) as count_of_appoints
from have
group by id;
quit;
I think there are only 3 for ID1, are you sure it;s 4?
data have;
input ID appt_date :mmddyy10.;
format appt_date mmddyy10.;
cards;
1 6/30/2018
1 7/7/2018
1 7/18/2018
1 7/28/2018
1 8/6/2018
1 9/20/2017
2 6/17/2018
2 6/28/2018
2 7/5/2018
2 7/6/2018
;
proc sql;
create table want as
select id, sum( appt_date>=intnx('days',today(),28)) as count_of_appoints
from have
group by id;
quit;
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