how would i count distinct ID that are that have appointments after the next 28 days from today
ID appt_date
1 6/30/2018
1 7/7/2018
1 7/18/2018
1 7/28/2018
1 8/6/2018
1 9/20/2017
2 6/17/2018
2 6/28/2018
2 7/5/2018
2 7/6/2018
want
ID 1 has 4 appt after 28 days
ID 2 has 0 appt after 28 days
I think there are only 3 for ID1, are you sure it;s 4?
data have;
input ID appt_date :mmddyy10.;
format appt_date mmddyy10.;
cards;
1 6/30/2018
1 7/7/2018
1 7/18/2018
1 7/28/2018
1 8/6/2018
1 9/20/2017
2 6/17/2018
2 6/28/2018
2 7/5/2018
2 7/6/2018
;
proc sql;
create table want as
select id, sum( appt_date>=intnx('days',today(),28)) as count_of_appoints
from have
group by id;
quit;
I think there are only 3 for ID1, are you sure it;s 4?
data have;
input ID appt_date :mmddyy10.;
format appt_date mmddyy10.;
cards;
1 6/30/2018
1 7/7/2018
1 7/18/2018
1 7/28/2018
1 8/6/2018
1 9/20/2017
2 6/17/2018
2 6/28/2018
2 7/5/2018
2 7/6/2018
;
proc sql;
create table want as
select id, sum( appt_date>=intnx('days',today(),28)) as count_of_appoints
from have
group by id;
quit;
Are you ready for the spotlight? We're accepting content ideas for SAS Innovate 2025 to be held May 6-9 in Orlando, FL. The call is open until September 25. Read more here about why you should contribute and what is in it for you!
What’s the difference between SAS Enterprise Guide and SAS Studio? How are they similar? Just ask SAS’ Danny Modlin.
Find more tutorials on the SAS Users YouTube channel.