SGPLOT VBAR: increase space between group (not by color)

[NguyenThanhTra]

Hi all,

I'm trying to plot vbar with group option. The current results are as follows:

PROC SQL NOPRINT;
	CREATE TABLE TEMP00 AS 
		SELECT MAKE, ORIGIN, COUNT(*) AS NUM, MEAN(INVOICE) AS  INVOICE, MEAN(MPG_CITY) AS MPG_CITY
			FROM SASHELP.CARS
				GROUP BY MAKE, ORIGIN
					HAVING (CALCULATED NUM)>10
						ORDER BY ORIGIN, (CALCULATED INVOICE);
QUIT;

PROC SGPLOT DATA=TEMP00;
	VBAR MAKE/ RESPONSE=INVOICE GROUP=ORIGIN NOOUTLINE  MISSING ;
	VLINE MAKE/ RESPONSE=MPG_CITY GROUP=ORIGIN  Y2AXIS LINEATTRS=(COLOR=CX9CBA5F PATTERN=SOLID THICKNESS=2PX)  
		MARKERATTRS=(SYMBOL=CIRCLEFILLED COLOR=CX9CBA5F) MARKERS MISSING;
	TITLE "Summary data by Make";
	Y2AXIS LABEL="Mean MPG City";
	YAXIS LABEL="Mean Invoice";
	XAXIS LABEL="Make" DISCRETEORDER=DATA;
	LABEL INVOICE="Mean Invoice" MPG_CITY="Mean MPG City";
RUN;

The graph divides groups by color. What I want is a graph that divides the groups by distance. Please tell me how to do it.

Sincerely thank you,

 

[yabwon]

if you don't mind disgusting [😅] solution try this:

PROC SQL NOPRINT;
	CREATE TABLE TEMP00 AS 
		SELECT MAKE, ORIGIN, COUNT(*) AS NUM, MEAN(INVOICE) AS  INVOICE, MEAN(MPG_CITY) AS MPG_CITY
			FROM SASHELP.CARS
				GROUP BY MAKE, ORIGIN
					HAVING (CALCULATED NUM)>10
						ORDER BY ORIGIN, (CALCULATED INVOICE);
QUIT;

data TEMP01;
  set TEMP00 end=eof;
  by ORIGIN notsorted;
  output;
  if last.ORIGIN and not EOF;
    INVOICE = .;
    MPG_CITY = .;
    i + 1;
    MAKE = repeat(" ", i) !! "12"x;
    output;
run;

PROC SGPLOT DATA=TEMP01;
	VBAR MAKE/ RESPONSE=INVOICE GROUP=ORIGIN NOOUTLINE  MISSING /*!*/ NOZEROBARS /*!*/  ;
	VLINE MAKE/ RESPONSE=MPG_CITY GROUP=ORIGIN  Y2AXIS LINEATTRS=(COLOR=CX9CBA5F PATTERN=SOLID THICKNESS=2PX)  
		MARKERATTRS=(SYMBOL=CIRCLEFILLED COLOR=CX9CBA5F) MARKERS MISSING;
	TITLE "Summary data by Make";
	Y2AXIS LABEL="Mean MPG City";
	YAXIS LABEL="Mean Invoice";
	XAXIS LABEL="Make" DISCRETEORDER=DATA;
	LABEL INVOICE="Mean Invoice" MPG_CITY="Mean MPG City";
RUN;

result:

Bart