I don't know if this is really all that more direct than Arthur's solution but it has fewer lines of code... data havea;     set have;     array mn(24) month1-month24;     array nm(24) _TEMPORARY_;     array sb(24) _TEMPORARY_;     array lg(24) _TEMPORARY_;     do i = 1 to 24;     nm(i) = 0;     if mn(i) = 1 then sb(i) = 1;     else sb(i) = 0;     if mn(i) = 1 and i = 1 then nm(i) = 1;     else if sb(i) = 1 then nm(i) = (sb(i)) + (nm(i-1));     else nm(i) = 0;     end;     long = max(of nm );     do j = 1 to 24;     if nm(j) = long then lg(j) = 1;     else lg(j) = 0;     times = sum(of lg );     end; run; ... View more