How do I write a SAS function to calculate the hypergeometric distribution of there being more than nine females surveyed from a sample of twenty?
In a large university, 40% of the students are female.
If a random sample of twenty students is selected, what is the probability that the sample will contain more than nine female students? (Round your answer to four decimal places.)
sample #of females surveyed:
0
3.6561584400629733e-05
1
0.000487487792008398
2
0.0030874226827198492
3
0.012349690730879413
4
0.034990790404158215
5
0.0746470195288711
6
0.12441169921478513
7
0.1658822656197136
8
0.17970578775468962
9
0.1597384780041684
10
0.11714155053639005
11
0.07099487911296365
12
0.03549743955648174
13
0.01456305212573616
14
0.004854350708578719
15
0.0012944935222876583
16
0.00026968615047659553
17
4.2303709878681673e-05
18
4.70041220874241e-06
19
3.2985348833280015e-07
20
1.0995116277760013e-08
I generated the table above using Python, so I imagine this data is likely inconsistent. However, it provided me with the correct probability for exactly four females. which was 0.0350.
I am currently trying to write a function for the excerpt below:
If a random sample of twenty students is selected, what is the probability that the sample will contain more than nine female students?
... View more