I am working on SAS version 9.4. I have a value LBSTRESC='<10.0'. I need to determine how many digits are present in LBSTRESC to the right of the decimal. I thought that the FINDC function would be appropriate. I tried several different combinations of startpos and modifier arguments shown below (and possibly more that produced unexpected results):     lbstresc='<10.0';   num=findc(lbstresc,'.',-1); num=findc(lbstresc,'.','b'); num=findc(lbstresc,'.',-1,'b'); num=findc(lbstresc,'.',-10); num=findc(lbstresc,'.',-10,'b'); num=findc(lbstresc,'.',10,'b'); num=findc(lbstresc,'.',1,'b');       All of these attempts gave me num=0 or num=4. Can someone help me correctly execute this function so that I can get num=2, as in the decimal place is the second value from the right to the left? Thank you! ... View more

Hello, I'm using proc phreg to model several covariates of an outcome. The continuous variables need to be log transformed, but sometimes when I run the code it works while other times I get the following error: ERROR: An illegal argument is used in the function call in statement number 1 at line 13        column 1.        The statement was:     1     (13:1)     logpreedin = LOG( preedin=0 ) I get that I can't expect SAS to calculate the log of zero, but can someone explain to me why it sometimes shows outputs for both the model and assess statements with logpreedin and sometimes I get the above error? Here's the code: proc phreg data=lchs.thesis_event; class trimst: outcome; logpreedin=log(preedin); model time*pregint24(0)=depo bfeed outcome prev_unplanned logpreedin postedin prop_fps kept_ps sex_nocondom/ties=efron; assess var=(logpreedin) ph/resample; run; Than ... View more