How can I get the table below:   id month1 month2 month3 month4 math1  math2 math3 math4 1 1 2 3 4 10 15 24  . 2 1 2 3 4  . 15  . 12 3 1 2 3 4 15 18 17 13     My code below give the following table   id month1 month2 month3 month4 math1  math2 math3 math4 1 1 2 3  . 10 15 24  . 2 2 4  .  .  . 15  . 12 3 1 2 3 4 15 18 17 13   data tic; input id country$ month math; datalines; 1 1 10 1 2 15 1 3 24 2 2 15 2 4 12 3 1 15 3 2 16 3 3 17 3 4 15 ; run; proc sort data=tic; by id; run; data tot(drop=month math); retain month1-month4 math1-math4; array tat{4} month1-month4; array kat{4} math1-math4; set tic; by id; if first.id then do; i=1; do j=1 to 4; tat{j}=.; kat{j}=.; end; end; tat(i)=month; kat(month)=math; if last.id then output; i+1; run;  What I want is to be able to produce the first table not the second table. The problem is with being able to sequentially number each column to tally with the column number per each id. any help is highly appreciated.   Thanks ... View more

I have a data in this format: id       years sex state 100002  0       0    1 100002  1       0    1 100002  2       0    2 100002  3       0    2 100002  4       0    2 100002  5       0    3 100004  0       1   1 100004  1.2    1   1 100004  2.4    1   1  and I want to create additional new three columns ( "start" & "end" out of "state", and "time" out of "age") such as the one below id          years sex state start End Time 100002    0       0    1       1    1      1 100002    1       0    1       1     2     2 100002    2       0    2       2     2     3 100002    3       0    2       2     2     4 100002    4       0    2       2     3     5 100004    0       1   1        1    1   1.2 100004  1.2      1   1         1    1   2.4  Please is there anyone who can help me out with this in SAS. Thanks I really appreciate. ... View more