In a library (consisting of one single directory) I need to create a data view. It should not depend on what name the user likes to give to the library. How can such a view be created?   For example, say we have a data set:   data "/tmp/dataset"; run; Then it is straightforward to create an SQL view as follows:   proc sql; create view "/tmp/sqlview" as select * from "/tmp/dataset"; quit; However I don't see how to create a data view in a similar way. The following code fails with the error "Expecting a name.": data "/tmp/dataview" / view = "/tmp/dataview"; set "/tmp/dataset"; run; Is there a way to achieve what I need? ... View more