@yesidgranadosv wrote: data _null_; call symputx('Fetch_COM', put(intnx ('month',today(),-2, 'b') + 27 ,yymmddn8.) ); run; I HAVE THE VARIABLE "Fetch COM"  SHE GIVES ME AS a RESULT 20190228  I NEED a VARIABLE TO DELIVER ME AS a RESULT 20190402  THE CURRENT DATE WITH DAY 2 That's not quite correct and please don't type in all upper case, it's the equivalent of yelling.    You're creating a macro variable, named Fetch_CON, that is the second day of the current year and month. You do not have a variable with that value nor are you using data from a data set.   TODAY() returns the current date INTNX() moves that date to the beginning of the month, since the first parameter is month and the last paramter is 'b' for beginning of the month.  +1/27 adds the number of days to the month as needed. YYMMDDN formats the date to appear in your desired format, although it's still a SAS date underneath. If you're planning to work more with dates and macro variables, I highly recommend reading the date and time tutorials here, you'll save yourself a lot of time: https://communities.sas.com/t5/SAS-Communities-Library/Working-with-Dates-and-Times-in-SAS-Tutorial/ta-p/424354   or more specifically, this PDF file attached.   ... View more

%let currentYear = %sysfunc(today(), year4.); %put &currentYear.;   TODAY() returns todays date.  %SYSFUNC() takes two parameter, a SAS function (TODAY()) and the format used. YEAR4 converts it to the year. ... View more

@yesidgranadosv wrote: Thank you Very Much, the truth if I work, but in this case I need to bring the 16th of each month Current month? Previous Month? Next month? data _null_; date= mdy(month(today()),16, year(today())); call symputx('CurrentMonthFetch_', put(date,yymmddn8.) ); date= mdy(month(intnx('month',(today()),-1)),16, year(intnx('month',(today()),-1))); call symputx('PrevMonthFetch_', put(date,yymmddn8.) ); run; %put CurrentMonthFetch_ = &CurrentMonthFetch_.; %put PrevMonthFetch_ = &PrevMonthFetch_.; The INTNX function does support a "middle" options such as   data _null_; date = intnx('month',today(),-1,'middle'); put date yymmddn8.; run; Which may or may not be exactly what you want but may make more sense for February with the 14th as middle in most years, or 15 for months with 30 days. ... View more