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amoreau1
‎09-01-2015
  • 5 Posts
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Cross-validation

by Calcite | Level 5 in SAS Procedures
‎07-04-2012 04:24 AM
‎07-04-2012 04:24 AM
To perform cross-validation, we need to have sufficient data to be able to split the full set of data into several (at least 2) subsets of data. My question is based on why number of observations, can we say that cross-validation can be performed. (I have 800 data) Thanks. ... View more

Re: Graph with bars using HILOT interpolation - URGENT

by Calcite | Level 5 in SAS Procedures
‎06-08-2012 12:02 PM
‎06-08-2012 12:02 PM
  symbol1 interpol=join ^      c=black      line=1      width=2; symbol2 interpol=hilot      c=black      cv=black      line=1      ci=black      width=2;   proc gplot data=final_; plot mean2*Visn low_up2*Visn / overlay haxis=axis1 vaxis=axis2 legend=legend1; run; quit; In Mean2 variable I have the mean per timepoint In Low_up2, I have lower and upper CI values (it means that for the same visit, I have 2 lines : 1 line is mean + lower CI and 1 line is mean + upper CI. Thanks. ... View more

Graph with bars using HILOT interpolation - URGENT

by Calcite | Level 5 in SAS Procedures
‎06-08-2012 05:24 AM
‎06-08-2012 05:24 AM
I need to create a graph like this (see attached) i.e. the mean including 95%CI using proc gplot: I use in the SYMBOL statement i=hilot to join the lower and the upper limit but SAS always includes the "---" at the middle of the 2 values. Is that possible to do not have it? Or do you have an other method to create such output? Thanks, ... View more

Re: Geometric mean in log base 10

by Calcite | Level 5 in SAS Procedures
‎06-08-2012 04:56 AM
‎06-08-2012 04:56 AM
Dear Steve, Thanks for your reply. Just to clarify, if I do 10**(mean_of_log_values), it is not equal to log(10)*exp(mean_of_log_values). I found the same result if I do exp(mean_of_log_values * log(10). So, what is the good formula? Thanks. ... View more

Geometric mean in log base 10

by Calcite | Level 5 in SAS Procedures
‎06-07-2012 03:33 AM
‎06-07-2012 03:33 AM
I need to calculate the geometric mean of data. These data are first transformed in log10. Then I do the arithmetic mean of these log10 values and then i do the exponential of the arithmetic mean.   Do you confirm I am right?   (I find very different values from arithmetic mean so I am not sure I do the calculation correclty). Moreover, someome told me that I should do GM = exponential of the arithmetic mean * log(10) (log function is the natural logarithm in SAS) and not just GM = exponential of the arithmetic mean   Thanks.for your help ... View more
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‎09-01-2015 07:11 AM
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