I don't quite understand your question, but I think you want to know the mean difference between age1 of 1 and 3 (for example) for males. The third contrast will do this, but I show the first two so you can see the steps. estimate 'm age 1' int 1 sex 1 0 age1 1 sex*age1 1; estimate 'm age 3' int 1 sex 1 0 age1 3 sex*age1 3; estimate 'm, age 3-1 ' age1 2 sex*age1 2; Note the the last estimate is the difference between the first two (which give you means for age 1 and age 3, both for males only [the first level of sex]). WIth the difference, terms like the intercept and sex main effect cancel. By the way, there are only two levels to your sex*age1 interaction, so your estimate statements will not work.
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