About rajeshV89

PaigeMiller · ‎05-21-2021

Repeating: Please run this command options mprint; and run your program again SHOW US the LOG from running this macro (all of the LOG from this macro, 100%, every single character, do not chop parts out)

rajeshV89 · ‎05-05-2021

It's working fine..thanks for the information..

bsd70 · ‎04-16-2021

If leap year and month of February then end day (extra day) should be 29 and not leap year and month of February then end day should be 28. Also, end of the day for January, March, May, July, August, October, December are 31 and end of the day for April, June, September, November are 30. Code required update using leap year and month. leapyear = (mod(year,4) = 0) and ((mod(year,100) ne 0) or (mod(year,400) = 0));

rajeshV89 · ‎05-22-2018

here i hot one solution: data want; input sdate $10.; format sdate_new yymmdd10.; sdate_new=input(sdate,nd8601da.); cards; 2009-10-14 2010-12-24 2001-03 2006-06 2012 2002-03-27 2003-02-03 ; run;

rajeshV89 · ‎03-19-2018

thanks for ur answer... i got to know the process the proc freq does... again thanks..

rajeshV89 · ‎03-19-2018

very thankful to the code given by u... i want become a good programmer in sas... i need ur valuable suggestions... kudos in advance..

Ksharp · ‎03-17-2018

options datestyle=mdy; Data new; Input sdtime anydtdtm32.; date=datepart(sdtime); format date date9. sdtime datetime.; Cards; 12:03:2003:12:13:23 ; Run; proc print;run;

rajeshV89 · ‎03-16-2018

how to get a datepart and timepart from anydtdtm. data without using character functions... data mh17; format edate datetime19.; input edate anydtdtm.; datalines; 12:01:2010:11:33:45 ; run;

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