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I have a data set of UB92 records. I am analyzing the costs and charges for various groups. Some groups are broken down into subgroups. For example, patient with a certain diagnosis are broken down into male and female. I've been using an unequal variance t-test two compare the mean charges of the diagnosis group against that of the non-diagnosis group. However, I have also calculated sex-adjusted mean charges by weighting the means of the male and female subgroups by the proportion of males and females in the standard population. This is the same as calculating sex-adjusted incidence rates. The problem is that now I am not sure how to calculate the two sample t-test to compare the sex-adjusted mean charges of the diagnosis group vs the non-diagnosis group. I don't want to simply use the sex-adjusted variance of the groups. This seems mistaken because the distribution of male and female in the sample groups is also a random variable, which adds extra variation to the adjusted means. Can I get some help? It would be much appreciated.
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