I'm trying to run this code but I'm getting the ERROR: variable WORD not found. Please help   data word; infile 'C:\Users\paul\Downloads\btt.dat' dlm=',' firstobs=2; input Bweight 8-11 Momeduc 29; run; proc sort data=word; by Momeduc; run; proc print; run; proc ANOVA data=word; class Momeduc; model word = Momeduc; run;   ... View more

This is the code:   data robot; infile 'C:\Users\paul\Downloads\Robot.dat' dlm=','; input HumT 1-5 HybT 7-11; run; proc univariate data= robot normal; qqplot HumT /normal (mu=est sigma=est); by HumT; run; proc ttest data=robot sides=2 alpha=0.05 h0=0; class HumT; var HybT; run;   The error:   ERROR: The CLASS variable has more than two levels.   The data:   185.4 180.4 .889 .997 146.3 248.5 .791 .959 174.4 185.5 .866 .821 184.9 216.4 .888 .914 240.0 269.3 .916 .973 253.8 249.6 .923 .925 238.8 282.0 .894 .912 263.5 315.9 .934 .965     ... View more

 Use the file to test if humans and hybrid differ for 1. Throughput and 2. Quality. Variable Columns Human throughput 1-5 hybrid throughput 7-11 Human quality 13-16 Hybrid quality 18-21   Check the assumptions and determine statistical model Find the test statistic and report p-value Made a decision So far I have the following code but let me know if this code is correct or if there is any other way to compare throughput and quality   data robot; infile 'C:\Users\\Downloads\gas.dat' dlm=',' firstobs=2; input HumT 1-5 HybT 7-11; diff=HumT-HybT; run; proc univariate data=robot normal; qqplot d /normal (mu=est sigma=est color=red 1=1); var diff; run; proc ttest data=robot side=2 alpha=0.05 h0=0; var diff; run; Two dependent samples with paired t-test.  For Ho: Uc – Ut = 0, t= 4.4689, and the p-value = 0.0231. The conclusion is to reject Ho and conclude that the reading human and hybrid throughput are significantly different. data robot; infile 'C:\Users\paul\Downloads\gas.dat' dlm=',' firstobs=2; input HumQ 13-16 HybQ 18-21; diff=HumQ-HybQ; run; proc univariate data=robot normal; qqplot d /normal (mu=est sigma=est color=red 1=1); var diff; run; proc ttest data=robot side=2 alpha=0.05 h0=0; var diff; run;   Here is the data: 185.4 180.4 .889 .997 146.3 248.5 .791 .959 174.4 185.5 .866 .821 184.9 216.4 .888 .914 240.0 269.3 .916 .973 253.8 249.6 .923 .925 238.8 282.0 .894 .912 263.5 315.9 .934 .965   ... View more

DATA two; infile 'C:\Users\paul\Downloads\btt.dat'; input Childid 1-4 Sex 6 Bweight 8-11 Gestage 13-14 Momage 16-17 Parity 19 Mdbp 31-23 Msbp 25-27 Momeduc 29 Mmedaid 31 socio 33 dbp5 35-37 sbp5 39-41 ht5 43-47 wt5 49-52 hdl5 54-57 ldl5 59-62 trig5 64-67 smoke5 69 medaid5 71 socio5 73;  if (Msbp >= 140) and (Mdbp >= 90) then class = 'Hypertension';  if (Msbp >= 140) and (Mdbp < 90) then class = 'Isolated systolic hypertension';  if (Msbp <= 140) and (Mdbp >= 90) then class = 'Isolated siastolic hypertension';  if (Msbp < 140) and (Mdbp < 90) then class = 'Normotensive'; run; proc print data=two (obs=10); var class; run; ... View more

I have the following code but want to limit the result to 10 instead of all the data. I thought firstobs=10 will make it happen but it did not. Please help!   DATA two; infile 'C:\Users\paul\Downloads\btt.dat' firstobs=10; input Childid 1-4 Sex 6 Bweight 8-11 Gestage 13-14 Momage 16-17 Parity 19 Mdbp 25-27 Momeduc 29 Mmedaid 31 socio 33 dbp5 35-37 sbp5 39-41 ht5 43-47 wt5 49-52 hdl5 54-57 ldl5 59-62 trig5 64-67 smoke5 69 medaid5 71 socio5 73; BMI = ht5 / wt5**2; run; proc print data=two; var Childid ht5 wt5 BMI; run; ... View more

DATA one; INPUT Type $ Circumference (inch) Height (ft) Crown (ft); Volume=0.319 * height * 0.0000163 * circumference^2; DATALINES; oak, black 222 105 112 hemlock, eastern 149 138 52 ash, white 258 80 70 cherry, black 187 91 75 maple, red 210 99 74 elm, american 229 127 104 ; RUN; PROC PRINT; var Volume; RUN; ... View more