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tinayong
‎02-02-2017
  • 3 Posts
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Re: using SUBSTR function extracts last 3 values

by Calcite | Level 5 in SAS Programming
‎02-02-2017 10:06 AM
‎02-02-2017 10:06 AM
output of the program 123 t21 at1 at1 ea2 ate b=substr(trt,length(trt)-2); length of the variabke is 8 and 8-2 =6, so for the first observation from the sixth position we get the values using substr function but from the second observation onwards the obs values decreasing but still substr function extracting last 3 values So am missing some logic here, may be am not thinking correct way ... View more

using SUBSTR function extracts last 3 values

by Calcite | Level 5 in SAS Programming
‎02-02-2017 08:16 AM
‎02-02-2017 08:16 AM
Hello All,   The below program using substr extracts last 3 values from obs, can anyone please help me to undersatnad the logic using substr function   input trt $; cards; treat123 treat21 treat1 treat1 trea2 lbdate ;run;   data abc; set temp; a=reverse(substr(left(reverse(trt)),1,3)); b=substr(trt,length(trt)-2); run;   Thanks  ... View more

doubt in understanding the code/procedure

by Calcite | Level 5 in Statistical Procedures
‎01-31-2017 04:02 AM
‎01-31-2017 04:02 AM
Hello All, I have a doubt in the below program, can anyone help me to find why they have used 0.5 while calculating logauc differecne, and also how to interpre the results data bioequiv; input subject sequence $ AUC_T CMAX_T AUC_R CMAX_R; logAUC_T=log(AUC_T); logCMAX_T=log(CMAX_T); logAUC_R=log(AUC_R); logCMAX_R=log(CMAX_R); cards; 01 TR 4321.7 360.11 4415.3 278.48 02 RT 2139.5 326.19 8846.2 605.45 03 RT 8295.5 578.66 7399.1 608.67 04 TR 5974.9 412.69 3071.2 196.19 05 TR 5121.9 423.98 7513.4 681.34 06 TR 18750.4 1359.86 17096.2 1191.91 07 RT 5609.7 1046.37 4498.8 392.45 08 RT 9040.9 733.80 7847.2 571.51 09 TR 21120.1 2403.67 22603.2 1449.63 10 RT 4865.3 669.17 8127.3 738.77 11 RT 7244.6 717.01 6249.4 364.80 12 TR 5543.7 409.05 4915.3 468.31 13 RT 9748.2 907.64 12218.5 884.73 14 RT 10257.4 995.68 6021.4 557.16 15 TR 10996.2 2434.96 15284.0 2509.14 16 TR 8031.0 476.31 2495.1 265.09 17 TR 6527.5 565.66 14736.4 1070.06 18 RT 6385.5 579.72 5118.7 483.04 19 RT 4077.1 297.07 2068.3 123.90 20 TR 7088.0 1334.96 6363.2 1064.23 21 RT 10689.3 1702.07 36108.5 2552.32 22 RT 4615.1 656.33 4551.9 403.34 23 TR 3792.8 441.33 10444.7 2057.38 24 TR 9429.5 1458.82 21239.7 1899.42 25 TR 4272.4 500.45 7247.8 945.48 26 RT 9442.7 905.35 3872.8 247.49 27 RT 7373.2 688.03 5522.3 449.56 28 TR 1883.5 139.61 3299.3 213.63 ; run; ************************************************************************* * Construct the intra-subject differences (times one-half) within each * * sequence. Then perform the statistical analysis. * *************************************************************************; data diff; set bioequiv; if sequence='TR' then logAUC_diff=0.5*(logAUC_T-logAUC_R); if sequence='RT' then logAUC_diff=0.5*(logAUC_R-logAUC_T); if sequence='TR' then logCMAX_diff=0.5*(logCMAX_T-logCMAX_R); if sequence='RT' then logCMAX_diff=0.5*(logCMAX_R-logCMAX_T); run; proc ttest data=diff alpha=0.10; class sequence; var logAUC_diff logCMAX_diff; title2 'Parametric Analysis'; run; Thanks ... View more
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