Hi Team,   I have read a lot of posts on that Error, but unfortunately none of these could solve my Error. So I have a dataset with the variables d_2006, erw_2006 for each year till d_2015 and erw_2015 and only one observation. I want to compute the SMR for all of these years within a macro. The variables smr, smr_u, and smr_o don't exist but should be created by the array.   data out_&number; set out; amph = "&nenner"; array smr [10] smr2006 smr2007 smr2008 smr2009 smr2010 smr2011 smr2012 smr2013 smr2014 smr2015; array smr_u [10] smr_u2006 smr_u2007 smr_u2008 smr_u2009 smr_u2010 smr_u2011 smr_u2012 smr_u2013 smr_u2014 smr_u2015; array smr_o [10] smr_o2006 smr_o2007 smr_o2008 smr_o2009 smr_o2010 smr_o2011 smr_o2012 smr_o2013 smr_o2014 smr_o2015; array erw_ erw_2006-erw_2015; array d_ d_2006-d_2015; do i = 2006 to 2015; if erw_{i} =0 then smr{i} = d_{i}; if erw_{i} >0 then smr{i} = d_{i}/erw_{i}; if d_{i} =0 then smr_u{i} =0; if d_{i} >0 & erw_{i} >0 then smr_u{i} = (d_{i}*((1-(1/(9*d_{i}))-(1.959963985/(3*sqrt(d_{i})))))**3)/erw_{i}; if d_{i} >0 & erw_{i} =0 then smr_u{i} = (d_{i}*((1-(1/(9*d_{i}))-(1.959963985/(3*sqrt(d_{i})))))**3); if erw_{i} >0 then smr_o{i} = ((d_{i}+1)*((1-(1/(9*(d_{i}+1)))+(1.959963985/(3*(sqrt(d_{i}+1))))))**3)/erw_{i}; if erw_{i} =0 then smr_o{i} = ((d_{i}+1)*((1-(1/(9*(d_{i}+1)))+(1.959963985/(3*(sqrt(d_{i}+1))))))**3); end; drop i; run; I've tried a lot of changes but stil get the ERROR: Array subscript out of range at...   Does anybody know where the fault is?   That would be great! Thanks a lot for help.     ... View more

Hey all,   I  am trying for a few days already to cut the last 8 digits from a string into a new variable and delete theses digits from the old one. It needs to be done over 100 variables, so it has to be within an array.   The original variables look like that:   1234b8:r:20060607 627::20071012 382027:l:20071212 182b::20071615 17293b:r:20081281   There are 100 of these kind. I tried scan and substr, that works for a single variable, but somehow within the array, the values with a character between the :: get lost.   The result should look like that:   Var                Date 1234b8:r       20060607 382027:l       20071212 182b             20071615 17293b:r       20081281     Probably there is an easy way to do that, but I can't find it.   Thank you in advance All the best!   ... View more